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Probability questions
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Re: Probability questions
I think the answer is 6.5
because if the probability of obtaining A is 0.5 and obtaining B is 0.35 and the probability of obtaining neither's intersection is o.2
then 0.5  0.2 is 0.3 and 0.35 0.2 is 0.15
and 0.15 + 0.5 is 0.65 and 0.3+0.35 is also 0.65...................right?
someone please help me this is confusing
because if the probability of obtaining A is 0.5 and obtaining B is 0.35 and the probability of obtaining neither's intersection is o.2
then 0.5  0.2 is 0.3 and 0.35 0.2 is 0.15
and 0.15 + 0.5 is 0.65 and 0.3+0.35 is also 0.65...................right?
someone please help me this is confusing
Thimodya/Waspinator Posts : 10
Points : 10
Join date : 20101003
Re: Probability questions
I think that it's 0.45.
I did the same thing as Timmy, but instead I added 0.3 to 0.15.
But it could be 0.2.
Neither's intersection is the middle bit, isn't it. So it would be 0.2
So confused
I did the same thing as Timmy, but instead I added 0.3 to 0.15.
But it could be 0.2.
Neither's intersection is the middle bit, isn't it. So it would be 0.2
So confused
Federico Posts : 8
Points : 10
Join date : 20101003
Re: Probability questions
freddy i dont think A'∩B' is the middle section. Mr safdar wouldnt give us a question with the answer writen in front of us.Federico wrote:I think that it's 0.45.
I did the same thing as Timmy, but instead I added 0.3 to 0.15.
But it could be 0.2.
Neither's intersection is the middle bit, isn't it. So it would be 0.2
So confused
im not too sure if 0.3 to 0.15s wrong though
so i also think its 0.45
the letters in bold give off a truth
fergus Posts : 18
Points : 29
Join date : 20101003
Age : 108
Re: Probability questions
fergus wrote:freddy i dont think A'∩B' is the middle section. Mr safdar wouldnt give us a question with the answer writen in front of us.Federico wrote:I think that it's 0.45.
I did the same thing as Timmy, but instead I added 0.3 to 0.15.
But it could be 0.2.
Neither's intersection is the middle bit, isn't it. So it would be 0.2
So confused
im not too sure if 0.3 to 0.15s wrong though
so i also think its 0.45
not bad fergus but thats not a good hidden message and i think that A'∩B' is anything that is not A intersects with anything that is not B so the entire outside of both circles
we want to find where A and B both occur so what we want is the probability of A∩B however where i am having trouble finding that.
the letters in bold give off a truth
Luka a.k.a GodOfRandom Admin
 Posts : 13
Points : 14
Join date : 20101003
Re: Probability questions
I think the answer is 0.05
because [p(A'∩B') = 0.2] is the probability of obtaining neither's intersection,
and we want to find p(A and B), middle section.
p(A) = 0.5 , p(B) = 0.35 , p(A'∩B') = 0.2 , and I think E = 1
E  p(A'∩B') = p(A∪B)
1  0.2 = 0.8 > so, p(A∪B) = 0.8
p(A∪B) = p(A) + p(B)  p(A∩B)
0.8 = 0.5 + 0.35  p(A∩B)
∴ p(A∩B) = 0.5 + 0.35  0.8 = 0.05
because [p(A'∩B') = 0.2] is the probability of obtaining neither's intersection,
and we want to find p(A and B), middle section.
p(A) = 0.5 , p(B) = 0.35 , p(A'∩B') = 0.2 , and I think E = 1
E  p(A'∩B') = p(A∪B)
1  0.2 = 0.8 > so, p(A∪B) = 0.8
p(A∪B) = p(A) + p(B)  p(A∩B)
0.8 = 0.5 + 0.35  p(A∩B)
∴ p(A∩B) = 0.5 + 0.35  0.8 = 0.05
Jihye Choi Posts : 2
Points : 2
Join date : 20101011
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